F(x)=x^2+80x+144

Solution for F(x)=x^2+80x+144 equation:

(F)=F^2+80F+144

We move all terms to the left:

(F)-(F^2+80F+144)=0

We get rid of parentheses

-F^2+F-80F-144=0

We add all the numbers together, and all the variables

-1F^2-79F-144=0

a = -1; b = -79; c = -144;
Δ = b2-4ac
Δ = -792-4·(-1)·(-144)
Δ = 5665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-\sqrt{5665}}{2*-1}=\frac{79-\sqrt{5665}}{-2}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+\sqrt{5665}}{2*-1}=\frac{79+\sqrt{5665}}{-2}
$